Two children went to town to sell their eggs, one had more in her basket than the other; the one who had the most said to the other, “Give me one of your eggs, and then I shall have double the number you have.”-”No”, said the other; “give me one of yours, and then we shall have equal”.
How many eggs had each of these children?
(answers to show in 1-2 days)
x=# of eggs the kid with the most has
y=# of eggs the kid with the least has
x+1=2(y-1)
x+1=2y-2
x=2y-3
x-1=y+1
x=y+2
-(x=2y-3)
0=-y+5
y=5
x=7
1 and 3, i think.^-^
7 and 5. Child with more eggs = x , child with less = y. From the first statement, if 1st gets one more egg, she will have twice what the 2nd has: x + 1 = (y – 1)2 or x = 2y -3 . From the second statement, if 1st gives 2nd 1 egg, they will have an equal number:
x – 1 = y +1 or x = y + 2 . So y + 2 = 2y – 3, then y = 5 and x = 7. I know (mom’s a math geek but I guessed it first, then had to prove it – to myself I guess) Thanks for all the fun – your site is wonderful! (Still no red dot….. yeah!)
7 and 5.
If the girl with more eggs takes one from the other.
7+1=8 which is two times as much as 5-1=4
If the girl with more eggs gives one to the other.
7-1=6 is equal to 5+1=6
child with most egg has 7
child with fewest has 5
7+1= 8 = 2*(5-1)
and
7-1 = 6 = 5+1
Also, I think the children should go for option two
Girl with most = 5 eggs
Girl with least = 4 eggs
The Child with more eggs had 3 eggs and the other had 2 eggs
7 and 5
First child (x), Second child (y)
x > y
x + 1 = 2y ; x = y + 1
Answer: First child = 3 eggs, Second child = 2 eggs
The child with more eggs has 7, the child with less has 5.
Let x= number of eggs (more)
Let y = number of eggs(less)
x+1 = 2 (y-1) ; one egg from less to more is twice
x – 1 = y + 1 ; one egg from more to less is equal
Solve for two equations, two unknowns
5 and 7
they both have no eggs
5 and 7.
I think its 7 and 5?
7+1=8, 5-1=4. 8 is double 4 (8 is 2/3rds of the total)
7-1= 6, 5+1=6 Both have equal amounts.
Both numbers are odd. The total number of eggs is even
The total number of eggs can be equaly divisable by 3 without any fractions
etc
Some of my workings are shown bellow
Where it says “Give me one of your eggs, and then I shall have double the number you have.” this indicates this person would then have 2/3rds of the eggs. Also this indicates that this child must have had an odd number of eggs, and now has an even number of eggs. As half of 5 does not go unless half eggs are involved.
For the other side of this where it says “No”, said the other; “give me one of yours, and then we shall have equal”. Indicates the total number of eggs must be an even.
Both children MUST have an odd number of eggs. Child 1 because if given 1 more egg from child 2, would have double that of child 2. Half of an odd number would leave a spare half egg. (Assuming no half eggs are present in this puzzle).
Child 2 because if given 1 more egg from child 1, both would have equal numbers of eggs. sounless half eggs are involved the total number of eggs are even.
The answer could not be 1 and 2 because
1: the total eggs are odd, and
2: subtract 1 from 1 and you would have 0 which you cannot have twice as much as 0.
3: both numbers are not odd
The answer could not be 2 and 4 because
1: Both numbers are even
2: subtract 1 from 2 and add it to 4 gives 5, which is not double 1.
3: 5 is an odd number
etc
The answer could not be 3 and 6 because
1: the total of 3+6 is odd
2: 6 is an even number
3: subtract 1 from3 and add it to 6. 7 is not double 2
4: 7 is an odd number
5: subtract 1 from 6 and add it to 3. 5 is not equal to 4
6: 5 in an odd number
etc
The answer COULD be 5 and 7 becaude
1: both numbers are odd
2: Add 5 and 7 together you get a total of 12 which is even.
3: 12 is equaly divisable by 3 without any fractions.
4: subtract 1 from 5 and add it to 7 which gived you 8 and 4. 8 is double 4
5: 8 is even
6: 8 is 2/3rds of 12
etc
I think one answer can be: child A= 7, child B= 5
explanation:
1) give 1 more and i have the double of yours : A=8, B=4
2)No, give one more and we shall be equal: A=6, B=6
Equations:
from 1) A + 1 = 2(B – 1)
from 2) A – 1 = B + 1
—>B=5—> A=7
Lateral thinking solution i guess(kidding): child A =111, child B=11 give 1 of yours and i shall double the number you have: “1111″, No give one of yours and we should equal: 11-11=0 (definition of equality)
One child has x eggs, other has y eggs
1. y gives 1 egg to x
x+1 = 2(y-1) (DOUBLE)
2. x gives 1 egg to y
x-1 = y+1 (EQUAL)
Simplify and we get
y=5, x=7
Q.E.D.
one girl had 4 eggs and the other had 5 eggs
answer is 7 and 5…..girl with 7 takes 1 egg she gets 8 the other girl left with 4 i.e. double, and if the girl with 5 takes 1 egg she gets 6 the other girl left with 6 i.e. equal! easy……..no it was a bit tricky at first!
5 and 4 eggs
Simple algebra.
x= eggs of person A
y= eggs of person B
1) y+1=2(x-1)
2)y-1=x+1
—Compare them and you get:
x= 5 eggs
y= 7 eggs
That’s it
I did trial & error, knowing that the total number of eggs have to be an even number if they can have the equal number of eggs
I got 5 & 7 =12
The mean one who wanted to have double would have had the 7, turned into 8 which would be twice as much as 4
Then, if the mean one actually gave one away, it would be 6 and 6 which would be equal.
i haven’t thought it through that much, but i think it’s 7 and 5..
1st child had 7 eggs and 2nd child had 5 eggs
One basket 1 contains 4 eggs & basket 2 has 5 eggs
7&5…
according to the question, if the greater no of eggs is say x and lesser no of eggs is say y, then two equations are formed:
x+1 = 2(y-1) and
x-1 = y+1
using these we get,
x = 7 and y = 5
thats it………..
as we can see from some of the responses submitted above, this one was a bit tricky. Several very good explanations are given for the answer, which is 5 & 7
2 and Zero