i made it look like a “I”, with two lines down the center. That way, there would be a line up top, and a line on the bottom, two vertical lines connecting the top and bottom, and the diagonals would be 5 and 6.

If you layout two sets of four coins horizontaly, with one set above the other. Then place a coin above the two end coins on the top row and a coin bellow the end two coins on the bottom row.

This gives you Two Horizontals, Two Verticals and Two diagonals each with four coins.

cool, there are more than two ways of doing it, but always using each coin in two rows with possible combination of (diagonal,diagonal), (diagonal, vertical),(diagonal,horizontal),(horizontal,vertical).

THE “I” AND THE “H” HAVE THE SAME DISPOSITION OF COINS, BUT THE WHOLE FORMATION ITS ROTATED, SO I COUNT THOSE TWO AS ONE, THE 5 TO 5 ITS TWO, AND THE FIRST I MADE AND HIS ROTATION MAKES THREE

The 2 answers I had in mind were the ‘I’ configuration, as several have pointed out above, and the ‘star’ arrangement, as Rosey and Suineg describe & parallax links to.

2 stacks of six coins each… I think the point of this puzzle was to think outside 2 dimentions. When you stack coins vertically you can count to four – three times in each stack.

OOOOOO

OOOOOO

There are many great answers to this! Well done everyone!

I agree with aaron hergert if you stack them there are many ways this can be achieved. Including making the six four coin rows with only eight coins.
Just form a box such as this however each coin has one coin on top of it while excluding the 4 unnecessarry ones:

jason| Guest September 24th, 2007 - 1:37 pmi made it look like a “I”, with two lines down the center. That way, there would be a line up top, and a line on the bottom, two vertical lines connecting the top and bottom, and the diagonals would be 5 and 6.

parallax| Guest September 24th, 2007 - 4:48 pmNot sure, but how about these:

http://i225.photobucket.com/al...../coins.jpg

Ian| Guest September 24th, 2007 - 6:31 pmit is in the form of a H with a big middle part

0 0

0 0 0 0

0 0 0 0

0 0

2 diagonal

2 horrisontal

2 vertical

Ian| Guest September 24th, 2007 - 6:32 pmdidn’t come out right!!!!!!!!!!!!!!!

just move the second ones on the top and bottom to the edge so it makes an H shape

Shawn| Guest September 25th, 2007 - 10:59 amIf you count diagonals and columns as “rows,” then you can make an “H” with 6 rows of 4 coins each:

X X

X X X X

X X X X

X X

Shawn| Guest September 25th, 2007 - 11:01 amOops, this system doesn’t count spaces.

X….X

XXXX

XXXX

X….X

Deejam| Guest September 25th, 2007 - 12:28 pmone of the way

http://img222.imageshack.us/im.....wereb0.jpg

Rosey| Guest September 25th, 2007 - 2:57 pmOne is a six-pointed star. I’m working on another.

Will| Guest September 25th, 2007 - 5:01 pmI think:

O O

OOOO

OOOO

O O

Will| Guest September 25th, 2007 - 5:03 pmOops, It diddnt come out as intended:

o–o

oooo

oooo

o–o

Will| Guest September 25th, 2007 - 5:16 pmTry again : If this does not work. I am trying to make an ‘H’ with 2 horizontal components.

O O

O O O O

O O O O

O O

scott k| Guest September 25th, 2007 - 7:39 pmcan’t figure this out, the closest I can come is to make a circle haha

tina| Guest September 25th, 2007 - 10:03 pmMine looks like an “H” with a double line going across. Same as the “I” but sideways.

MoysieGT| Guest September 26th, 2007 - 2:44 amIf you layout two sets of four coins horizontaly, with one set above the other. Then place a coin above the two end coins on the top row and a coin bellow the end two coins on the bottom row.

This gives you Two Horizontals, Two Verticals and Two diagonals each with four coins.

Joe| Guest September 26th, 2007 - 4:03 amhttp://i3.photobucket.com/albu.....uzzle1.jpg

http://i3.photobucket.com/albu.....uzzle2.jpg

Bob Squirrel| Guest September 26th, 2007 - 6:19 amI think this is an easy one.

the keyword being I

As in, I.

oooo

oo

oo

oooo

lol

Bob Squirrel| Guest September 26th, 2007 - 6:20 amoooo

..oo

..oo

oooo

ok better

suineg| Guest September 26th, 2007 - 9:55 amthe problem is solve in any configuration that you can used any coin in 2 of the lines: i think this is one solution too:

O O

O O O

O O

O O O

O O

suineg| Guest September 26th, 2007 - 10:01 ami does not save the space wait a minute..

O…….O…..O

……………….

O……O……O

….O……O

O……O……O

………………..

O…….O……O

i hope this work

suineg| Guest September 26th, 2007 - 10:07 amcool, there are more than two ways of doing it, but always using each coin in two rows with possible combination of (diagonal,diagonal), (diagonal, vertical),(diagonal,horizontal),(horizontal,vertical).

suineg| Guest September 26th, 2007 - 10:14 ami made seven ups

suineg| Guest September 26th, 2007 - 10:16 ambut with 14 coins, i made up the problems again

suineg| Guest September 26th, 2007 - 10:17 amtake the two middle coins of the upper row and the lower row and you get 6 rows of 4 coins with 12 coins

Justin| Guest September 26th, 2007 - 12:42 pmok, it’s easier when you use a rather liberal definition of the word row

suineg| Guest September 26th, 2007 - 6:38 pmits like this:

O………………O

O……..O…….O

…..O……..O

O……..O…….O

O………………O

suineg| Guest September 26th, 2007 - 7:03 pmANOTHER SOLUTION I CALL 5 “TO” 5 IS THIS:

………O

O…O….O…O

…O………O

O…O….O…O

………O

suineg| Guest September 26th, 2007 - 7:08 pmTHE “I” AND THE “H” HAVE THE SAME DISPOSITION OF COINS, BUT THE WHOLE FORMATION ITS ROTATED, SO I COUNT THOSE TWO AS ONE, THE 5 TO 5 ITS TWO, AND THE FIRST I MADE AND HIS ROTATION MAKES THREE

RK| Profile September 26th, 2007 - 11:26 pmJoe- your 1st configuration was interesting; I think I follow, but just to be sure, can you explain what you did?

RK| Profile September 26th, 2007 - 11:44 pmThe 2 answers I had in mind were the ‘I’ configuration, as several have pointed out above, and the ‘star’ arrangement, as Rosey and Suineg describe & parallax links to.

Joe| Guest September 27th, 2007 - 1:40 amJust stack the coins in the 12, 3, 6, and 9 o’clock positions.

http://i3.photobucket.com/albu.....zle1-1.jpg

RK| Profile September 27th, 2007 - 7:55 amJoe- that works too, nice.

suineg| Guest September 28th, 2007 - 1:08 pmi found another way:

………………….OO

………………….OO

………………..OOOO

………………O..OO..O

I THINK THIS WORK AND IS A DIFFERENT WAY.

Kyle| Guest October 8th, 2007 - 8:18 pm0 0

0000

0000

0 0

Left and Right rows (vertical), two middle rows (horizontal), top left to bottom right row (diagonal), bottom left to top right (diagonal).

aaronhergert| Guest October 23rd, 2007 - 7:12 am2 stacks of six coins each… I think the point of this puzzle was to think outside 2 dimentions. When you stack coins vertically you can count to four – three times in each stack.

OOOOOO

OOOOOO

There are many great answers to this! Well done everyone!

Brian| Guest November 14th, 2007 - 11:54 pmI agree with aaron hergert if you stack them there are many ways this can be achieved. Including making the six four coin rows with only eight coins.

Just form a box such as this however each coin has one coin on top of it while excluding the 4 unnecessarry ones:

0 0

0 0

hussain| Guest November 29th, 2007 - 7:08 pmI hav figured out the solution it tuk me quite a while but…i finally got da ansa here it is:

0 0

0000

0000

0 0