School-Safe Puzzle Games

## Ancient coin arrangement puzzle

For this puzzle, arrange the 12 ancient coins in six rows, with four coins in each row.

Click on image below to play the puzzle in flash.

There are two winning configurations that I know of; will reveal submitted answers in a day or 2.

### 36 Comments to “Ancient coin arrangement puzzle”

1. jason | Guest

i made it look like a “I”, with two lines down the center. That way, there would be a line up top, and a line on the bottom, two vertical lines connecting the top and bottom, and the diagonals would be 5 and 6.

2. parallax | Guest

Not sure, but how about these:
http://i225.photobucket.com/al...../coins.jpg

3. Ian | Guest

it is in the form of a H with a big middle part
0 0
0 0 0 0
0 0 0 0
0 0

2 diagonal
2 horrisontal
2 vertical

4. Ian | Guest

didn’t come out right!!!!!!!!!!!!!!!
just move the second ones on the top and bottom to the edge so it makes an H shape

5. Shawn | Guest

If you count diagonals and columns as “rows,” then you can make an “H” with 6 rows of 4 coins each:

X X
X X X X
X X X X
X X

6. Shawn | Guest

Oops, this system doesn’t count spaces.

X….X
XXXX
XXXX
X….X

7. Rosey | Guest

One is a six-pointed star. I’m working on another.

8. Will | Guest

I think:

O O
OOOO
OOOO
O O

9. Will | Guest

Oops, It diddnt come out as intended:

o–o
oooo
oooo
o–o

10. Will | Guest

Try again : If this does not work. I am trying to make an ‘H’ with 2 horizontal components.

O O
O O O O
O O O O
O O

11. scott k | Guest

can’t figure this out, the closest I can come is to make a circle haha

12. tina | Guest

Mine looks like an “H” with a double line going across. Same as the “I” but sideways.

13. MoysieGT | Guest

If you layout two sets of four coins horizontaly, with one set above the other. Then place a coin above the two end coins on the top row and a coin bellow the end two coins on the bottom row.

This gives you Two Horizontals, Two Verticals and Two diagonals each with four coins.

14. Bob Squirrel | Guest

I think this is an easy one.

the keyword being I

As in, I.

oooo
oo
oo
oooo

lol

15. Bob Squirrel | Guest

oooo
..oo
..oo
oooo

ok better

16. suineg | Guest

the problem is solve in any configuration that you can used any coin in 2 of the lines: i think this is one solution too:

O O

O O O
O O
O O O

O O

17. suineg | Guest

i does not save the space wait a minute..

O…….O…..O
……………….
O……O……O
….O……O
O……O……O
………………..
O…….O……O
i hope this work

18. suineg | Guest

cool, there are more than two ways of doing it, but always using each coin in two rows with possible combination of (diagonal,diagonal), (diagonal, vertical),(diagonal,horizontal),(horizontal,vertical).

19. suineg | Guest

20. suineg | Guest

but with 14 coins, i made up the problems again

21. suineg | Guest

take the two middle coins of the upper row and the lower row and you get 6 rows of 4 coins with 12 coins

22. Justin | Guest

ok, it’s easier when you use a rather liberal definition of the word row

23. suineg | Guest

its like this:

O………………O

O……..O…….O
…..O……..O
O……..O…….O

O………………O

24. suineg | Guest

ANOTHER SOLUTION I CALL 5 “TO” 5 IS THIS:
………O
O…O….O…O
…O………O
O…O….O…O
………O

25. suineg | Guest

THE “I” AND THE “H” HAVE THE SAME DISPOSITION OF COINS, BUT THE WHOLE FORMATION ITS ROTATED, SO I COUNT THOSE TWO AS ONE, THE 5 TO 5 ITS TWO, AND THE FIRST I MADE AND HIS ROTATION MAKES THREE

26. RK | Profile

Joe- your 1st configuration was interesting; I think I follow, but just to be sure, can you explain what you did?

27. RK | Profile

The 2 answers I had in mind were the ‘I’ configuration, as several have pointed out above, and the ‘star’ arrangement, as Rosey and Suineg describe & parallax links to.

28. Joe | Guest

Just stack the coins in the 12, 3, 6, and 9 o’clock positions.
http://i3.photobucket.com/albu.....zle1-1.jpg

29. RK | Profile

Joe- that works too, nice.

30. suineg | Guest

i found another way:

………………….OO
………………….OO
………………..OOOO
………………O..OO..O
I THINK THIS WORK AND IS A DIFFERENT WAY.

31. Kyle | Guest

0 0
0000
0000
0 0

Left and Right rows (vertical), two middle rows (horizontal), top left to bottom right row (diagonal), bottom left to top right (diagonal).

32. aaronhergert | Guest

2 stacks of six coins each… I think the point of this puzzle was to think outside 2 dimentions. When you stack coins vertically you can count to four – three times in each stack.

OOOOOO

OOOOOO

There are many great answers to this! Well done everyone!

33. Brian | Guest

I agree with aaron hergert if you stack them there are many ways this can be achieved. Including making the six four coin rows with only eight coins.
Just form a box such as this however each coin has one coin on top of it while excluding the 4 unnecessarry ones:

0 0

0 0

34. hussain | Guest

I hav figured out the solution it tuk me quite a while but…i finally got da ansa here it is:

0 0
0000
0000
0 0