School-Safe Puzzle Games

## Complicated Family

In 2001, John and Jane married, and they each already had children from earlier marriages. Ten years later there was a feverish battle engaging the present family of twelve children. Jane ran to John and yelled, “Come at once! Your children and my children are fighting our children!”

As John & Jane now had each nine children of their own, how many were born during the ten years?

Answers to this challenge can be entered into the section below; submissions will automatically be revealed when time is up!

### 12 Comments to “Complicated Family”

1. RK | Founder | Profile

test

2. Bobo The Bear | PUZZLE MASTER | Profile

The wording is a little unclear, but I think it’s 3 from John’s first marriage, 3 from Jane’s first marriage, and 6 children together over the last 10 years.

3. Shawn | PUZZLE GRANDMASTER | Profile

6 were the spawn of John & Jane.

Jo + Ja + JoJa = 12
Jo + JoJa = 9
Ja + JoJa = 9

JoJa = 6

4. suineg | PUZZLE MASTER | Profile

Cool, lets see:
BMC= before 10 years marriage children (2001)
AMC= after 10 years marriage children (2011)
OIMC= Only in marriage kids (10 years span only)
TC= total children of John and Jane (shared and nonshared…are they? jaja I mean double counting the shared ones or the OIMC)
AMC= 12
TC= 9 + 9= 18
TC-AMC= 18-12= 6; BMC= 6
OIMC= AMC – BMC; OIMC= 6
Six children were born in the ten years span. Cool man.

5. Pookah | Profile

6

A+b+c=12
a+c=9
b+c=9

c-9+c-9+c=12

18-c=12
c=6

6. RK | Founder | Profile

The wording does make this one a bit tricky, but yes, the answer is 6.

Very good!

7. Leoandrex | Profile

12 children were born during the 10 years

8. Leoandrex | Profile

damn read the question again and realised its 6

9. Leoandrex | Profile

all children=12
18-12=6