School-Safe Puzzle Games

Complicated Family

In 2001, John and Jane married, and they each already had children from earlier marriages. Ten years later there was a feverish battle engaging the present family of twelve children. Jane ran to John and yelled, “Come at once! Your children and my children are fighting our children!”

As John & Jane now had each nine children of their own, how many were born during the ten years?

Answers to this challenge can be entered into the section below; submissions will automatically be revealed when time is up!

12 Comments to “Complicated Family”


  1. RK | Founder | Profile

    test


  2. Bobo The Bear | PUZZLE MASTER | Profile

    The wording is a little unclear, but I think it’s 3 from John’s first marriage, 3 from Jane’s first marriage, and 6 children together over the last 10 years.


  3. Shawn | PUZZLE GRANDMASTER | Profile

    6 were the spawn of John & Jane.


    Jo + Ja + JoJa = 12
    Jo + JoJa = 9
    Ja + JoJa = 9


    JoJa = 6


  4. suineg | PUZZLE MASTER | Profile

    Cool, lets see:
    BMC= before 10 years marriage children (2001)
    AMC= after 10 years marriage children (2011)
    OIMC= Only in marriage kids (10 years span only)
    TC= total children of John and Jane (shared and nonshared…are they? jaja I mean double counting the shared ones or the OIMC)
    AMC= 12
    TC= 9 + 9= 18
    TC-AMC= 18-12= 6; BMC= 6
    OIMC= AMC – BMC; OIMC= 6
    Six children were born in the ten years span. Cool man.


  5. Pookah | Profile

    6


    A+b+c=12
    a+c=9
    b+c=9


    c-9+c-9+c=12


    18-c=12
    c=6


  6. RK | Founder | Profile

    The wording does make this one a bit tricky, but yes, the answer is 6.


    Very good!


  7. Leoandrex | Profile

    12 children were born during the 10 years


  8. Leoandrex | Profile

    damn read the question again and realised its 6


  9. Leoandrex | Profile

    all children=12
    18-12=6


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