In 2001, John and Jane married, and they each already had children from earlier marriages. Ten years later there was a feverish battle engaging the present family of twelve children. Jane ran to John and yelled, “Come at once! Your children and my children are fighting our children!”
As John & Jane now had each nine children of their own, how many were born during the ten years?
Answers to this challenge can be entered into the section below; submissions will automatically be revealed when time is up!
test
six
The wording is a little unclear, but I think it’s 3 from John’s first marriage, 3 from Jane’s first marriage, and 6 children together over the last 10 years.
6 were the spawn of John & Jane.
Jo + Ja + JoJa = 12
Jo + JoJa = 9
Ja + JoJa = 9
JoJa = 6
Cool, lets see:
BMC= before 10 years marriage children (2001)
AMC= after 10 years marriage children (2011)
OIMC= Only in marriage kids (10 years span only)
TC= total children of John and Jane (shared and nonshared…are they? jaja I mean double counting the shared ones or the OIMC)
AMC= 12
TC= 9 + 9= 18
TC-AMC= 18-12= 6; BMC= 6
OIMC= AMC – BMC; OIMC= 6
Six children were born in the ten years span. Cool man.
6
A+b+c=12
a+c=9
b+c=9
c-9+c-9+c=12
18-c=12
c=6
The wording does make this one a bit tricky, but yes, the answer is 6.
Very good!
18
12 children were born during the 10 years
damn read the question again and realised its 6
all children=12
18-12=6