At a school musical practice session, there are 32 tambourinists, 80 triangle beaters, 64 drummers, 112 maracas shakers, and 48 singers. The music teacher assigns the children to equal sized groups. Each group has the same number of singers, and players of each instrument.
What is the largest number of groups possible? (no student is left out)
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test
I think the answer is 16 groups.
My reasoning was to take each number to their prime factorization, so:
2 to the 4 is the least common multiple and its 16, so 16 groups:
Each of this 16 groups would have: 2 tambourinists, 5 triangle beaters, 4 drummers, 7 maracas shakers and 3 singers.
Cool!!
173?
Dont know if I did this one too quickly and I am wrong but
16 groups each with
2 tambourinists, 5 triangle beaters, 4 drummers, 7 maraca shakers and 3 singers
I looked for the HIGHEST common denominator..
16 groups of 2 tambourinists, 5 triangle beaters, 4 drummers, 7 maracas shakers, and 3 singers. Simple factoring problem.
16 (the greatest common factor)
16 * 2 = 32
16 * 3 = 48
16 * 4 = 64
16 * 5 = 80
16 * 7 = 112
16.
The GCF of all the numbers is 16. Each group has 2 tambourinists, 5 triangle beaters, 4 drummers, 7 maracas shakers, and 3 singers.
There can be 16 groups (Each group has 2 tambourinists, 5 triangle beaters, 4 drummers, 7 maracas shakers, and 3 singers).
The largest number is 16
16
16 groups as 16 is the greatest common divisor to 32, 48, 64, 80, and 112
The maximum number of groups is 16 – giving 2 tambourine shakers, 5 triangle players, 4 drummers. 7 maracas shakers, and 3 singers per group.
Sounds like 16 groups with 21 musicians in each group.
16. It’s the greatest common factor.
Each group will have 2 tambourinists, 5 triangle beaters, 4 drummers, 7 maracas shakers, and 3 singers.
16
16
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