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Loading ...In the bottom of a well, 45 feet deep, there was a frog that started traveling toward the top. In his journey, he ascended 3 feet every day, but fell back 2 feet every night.
In how many days did he get out?
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Couple months back, a similar math brain teaser was posted.
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43
On the 43rd day the frog ascends from 42 ft. to 50 ft. so it is on the 43rd day that the frog reaches the top.
aaah! I mean the frog ascends from 42 ft. to 45 ft. on the 43rd day!
I guess that as he makes net progress of 1 foot per day the answer would be 1 day per foot until he got within 3 feet of the top and then one day more fot the last 3 feet as he would be able to leave the well before slipping down the following night.
With that in mind I make it 43 days in total.
43 days
43 days
43 days
43 days?
43 days
On the 43rd day the frog jumped up 3 feet from his previous night’s height of 42 feet, and escaped the well.
He might have escaped sooner, but Lassie only helps humans. Actually, collies are known for their particular disdain for amphibians at large.
The frog should ascend for 21 days to exit the 45-feet well.
its gotta be something like 42. he climbs up 1 foot every day total but when he gets to 42 the 3 he climbs in the day will get him out and he wont need to climb anymore or fall back. 43 ill say, 42 to get to 42 and then 1 more day.
42 days
I guess it depends… 43 days if the frog makes it to the edge of the well and climbs out or 44 days for it to pass the mark…
43 days
43 days to reach the top, but you know honestly unless frogs are a lot tougher than me I don’t think he ever made it. I mean he would have starved by then lol.
43, unless he is stupid, and then it will be 44
After 42 days, he’s up 42 feet. On the 43rd day, he ascends the 3 feet to the top.
41 days because on the 41st day he would clear the last two feet without slipping back down. (ie. he’d jump out of the well)
43
43
45 days… one foot each 24 hours
43 days. Every day he gained one foot, so he began each day at the level of the preceeding day’s number, so on day 42, he began at 41 feet, and climbed to 44 feet. On day 43, he began at 42 feet and climbed to 45 feet and was out.
42
I’m going to guess – 44 days.
First of all, yes, I did have a lot of time on my hands…
The graph illustrates progress made each day (in green) and lost each night (in red).
I conclude that the frog takes 44 days to exit the well, because though the frog reaches 45 feet on day 43, this just means that he is at the top of the well… not beyond it.
44 days.
The image didn’t show in my previous comment, so the link is here if anyone could be bothered accessing it!
http://a174.ac-images.myspacec.....2807d5.jpg
Hi Megan- don’t think the graph made it?
I believe the point you raise is similar to what Jay is saying, and is probably why Joe put a ‘?’ after his answer of 43 (and might explain John Highsmith’s comment and Amie’s answer of 44)
Not sure what others think – while the ‘official’ answer is ‘43′, in light of the way the question is worded- aren’t ‘43′ & 44′ both acceptable?
The frog will ascend 1 foot each day for 42 days and on the last day it’ll ascend 3 feet (because no night spent in the well on this day). Thus, the frog will exit the well on the 43rd day since beginning its climbing.
what kind of rock is the well made out of, thats the real question.
It took the frog 45 days to get out of the well. You subtract 3 feet from the original height (froggy going up) then add 2 after subtracting the original height from 3 (froggy going down).
I suspect Shamrock
You are all wrong except for Amie and Megan.
The correct answer is 44. I have programmed a flash simulator of this which you can try out yourselves, available on my website with the source code included.
http://www.motion2.net/frog.html
Enjoy
Oooops, my bad. I made a programming error, the correct answer is 43. Amie and Megan are wrong.
See my simulation
http://www.motion2.net/frog.html