School-Safe Puzzle Games

If 1/5 of a cluster of Panopyras flew to the Viper tree, one-third flew to the Leucomelas tree, three times the difference of these two numbers flew to a Prolemurius tree, and one Panopyra continued to fly about, attracted on each side by the fragrant Teylu and the Dinicthoid, what was the number of Panopyras?

Answers to this challenge can be entered into the section below; submissions will automatically be revealed when time is up!

neat picture courtesy of Brenda Adams

1. Hex | PUZZLE MASTER | Profile

I am not sure what is meant by ‘on each side’. I understand that 1 panopyra was left.

(1/5 + 1/3 + 3(1/3 – 1/5)x + 1 = x
x = 15

2. suineg | PUZZLE MASTER | Profile

Ok, I think it can be solved like this:
T= Total of Panopyras
1/5T fly to the VP tree
1/3T fly to the L tree
2/5T = 3(1/3- 1/5)Tfly to the P tree
1 keeps wandering around

From this you now that 14/15T = (3/15 + 5/15 + 6/15)T is the unknown, the remaining part thats is 1 Panopyra represent 1/15T for adding to a total number so:
1/15T = 1 therefore T = 15

Cool!

3. Shawn | PUZZLE GRANDMASTER | Profile

Must be 15, but my computer is telling me that a panopyra is a jellyfish. How do they fly?

4. Bobo The Bear | PUZZLE MASTER | Profile

15 Panopyras flew in this orchard of succulent delights.
(3 to the Viper, 5 to the Leucomelas, 6 to the Prolemurius, and 1 remained)

5. joe | Profile

if x is the total number (we need to find)
1/5 x fly off, another 1/3 x fly off to another tree, and then 3 times this difference
( 3 (1/3 x – 1/5 x ) fly off to another , and 1 is left flying about
so this gives us the following equation x the total is equal to all those we are told fly off:
x = 1/5 x + 1/3 x + 3 (1/3 x – 1/5 x ) +1

Solving for x gives us a total of
15

6. Mashplum | PUZZLE MASTER | Profile

15

1/5 = 3/15
1/3 = 5/15
5/15-3/15 = 2/15
3*(2/15) = 6/15
1 – 3/15 – 5/15 – 6/15 = 1/15
1/15 = 1 Panopyras

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