## Fly About

If 1/5 of a cluster of Panopyras flew to the Viper tree, one-third flew to the Leucomelas tree, three times the difference of these two numbers flew to a Prolemurius tree, and one Panopyra continued to fly about, attracted on each side by the fragrant Teylu and the Dinicthoid, what was the number of Panopyras?

*Answers to this challenge can be entered into the section below; submissions will automatically be revealed when time is up!*

neat picture courtesy of Brenda Adams

RK| Founder | Profile September 23rd, 2010 - 10:12 pmtest

Hex| PUZZLE MASTER | Profile September 24th, 2010 - 2:21 amI am not sure what is meant by ‘on each side’. I understand that 1 panopyra was left.

(1/5 + 1/3 + 3(1/3 – 1/5)x + 1 = x

x = 15

suineg| PUZZLE MASTER | Profile September 24th, 2010 - 7:11 amOk, I think it can be solved like this:

T= Total of Panopyras

1/5T fly to the VP tree

1/3T fly to the L tree

2/5T = 3(1/3- 1/5)Tfly to the P tree

1 keeps wandering around

From this you now that 14/15T = (3/15 + 5/15 + 6/15)T is the unknown, the remaining part thats is 1 Panopyra represent 1/15T for adding to a total number so:

1/15T = 1 therefore T = 15

Cool!

Shawn| PUZZLE GRANDMASTER | Profile September 24th, 2010 - 10:11 amMust be 15, but my computer is telling me that a panopyra is a jellyfish. How do they fly?

Bobo The Bear| PUZZLE MASTER | Profile September 24th, 2010 - 1:29 pm15 Panopyras flew in this orchard of succulent delights.

(3 to the Viper, 5 to the Leucomelas, 6 to the Prolemurius, and 1 remained)

joe| Profile September 27th, 2010 - 7:58 amif x is the total number (we need to find)

1/5 x fly off, another 1/3 x fly off to another tree, and then 3 times this difference

( 3 (1/3 x – 1/5 x ) fly off to another , and 1 is left flying about

so this gives us the following equation x the total is equal to all those we are told fly off:

x = 1/5 x + 1/3 x + 3 (1/3 x – 1/5 x ) +1

Solving for x gives us a total of

15

Mashplum| PUZZLE MASTER | Profile September 29th, 2010 - 8:23 am15

1/5 = 3/15

1/3 = 5/15

5/15-3/15 = 2/15

3*(2/15) = 6/15

1 – 3/15 – 5/15 – 6/15 = 1/15

1/15 = 1 Panopyras