12 Responses to “Impossible Math: Very Hard Puzzle”

1. 
   Joe | Profile (beta) May 14th, 2007 - 1:23 pm
   
   

   It’s probably not right, but if you take nine from six the only letter you can take away that they both have is “i”, so you get “sx.” Take ten from nine you get “ni”, and fifty from forty you get “or.” So you’re left with sx, ni, and or, which is six letters.

   
   
2. 
   Prairie Kittin | Profile (beta) May 14th, 2007 - 2:39 pm
   
   

   I can’t seem to get this one. The 0 being placed where it is throws the whole thing off. Therefore, my conclusion is that the 0 must be there for a reason. (I’m looking at patterns… or things like taking a block of 6 numbers and removing the number 9 from that block… that doesn’t work, and neither do any of the other pattern-manipulation things I’ve tried).
   Can we get a hint??
   Prairie

   
   
3. 
   Prairie Kittin | Profile (beta) May 14th, 2007 - 7:35 pm
   
   

   Ha!! I got it!!!

   Roman numerals!

   SIX - 9 (IX)= S
   9 (IX) - 10 (X) = I
   40 (XL) - 50 (L)= X

   SIX

   Prairie

   
   
4. 
   Dr. R.L. Kaplan | Profile (beta) May 14th, 2007 - 9:05 pm
   
   

   good going, Prarie- didn’t think anyone would get this for a couple days…

   
   
5. 
   Prairie Kittin | Profile (beta) May 14th, 2007 - 10:40 pm
   
   

   That was fun. It stumped me for a while! I wasn’t sure I was going to be able to get this one! LOL!!
   Prairie

   
   
6. 
   jason | Profile (beta) May 15th, 2007 - 6:45 am
   
   

   its a good think I didn’t post what I was going to say!!

   
   
7. 
   Juan Luis Roldán | Profile (beta) May 15th, 2007 - 8:46 am
   
   

   I made an adaptation to spanish language. It´s hard for me to translate it because my ENglish it´s not very goof, but it woul be something like:

   “I took six from the grapevine (”vid” in spanish), a hundred and fifty from the cabbage (”col”) and one was beside oneself (”Fuera de sí”). At last I had two (”dos”)”

   http://espejo-ludico.blogspot......-de-s.html

   
   
8. 
   Colleen | Profile (beta) May 20th, 2007 - 11:45 pm
   
   

   I had a pretty different approach…

   ((6-9) + (9- 10)) - (40-50)=
   -3 + -1 - (-10)=
   -4 + 10=
   6

   This way is kind of stretching it, though.

   
   
9. 
   kiki | Profile (beta) July 2nd, 2007 - 12:08 am
   
   

   9-6=3
   10-9=1
   50-40=10
   3+1=4
   10-4
   6
   theres ur solution!!!!!!!!!!

   
   
10. 
    Hreljin | Profile (beta) August 28th, 2007 - 12:12 pm
    
    

    789-456-123=210 then the sum of the digits is divisible by 3, so the numbers given in the problem is up to nine , so 9-3= 6!!! but what about the zero?!?! i’ll solve again maybe…

    
    
11. 
    Ray | Profile (beta) September 15th, 2007 - 10:25 am
    
    

    9 from 6 = -3
    10 from 9 = -1
    50 from 40 = -10

    -3 - -10 + -1 = 6

    
    
12. 
    swsint | Profile (beta) September 19th, 2007 - 8:43 pm
    
    

    Heres another solution. Start at 6 and count 9 numbers backwards so you will cross out 7. Then start at 9 and count back 10 you will cross out 9. The 50 from 40 is -10 so cross out 1 and 0 you are left with 6 numbers 2, 3, 4, 5, 6, 8

    
    

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