Grab a friend!

Ok, here’s the 1st puzzle I’ve seen where you can physically dual it out with a friend.  First you’ll need some string.  And if you’re at work, why not ask the person sitting next to you to give it a try?

Here we go:

Take 2 pieces of string and tie it around the wrists as shown below. The puzzle is for both of you to release yourselves without untying the string!

If you can solve this in your mind’s eye with pure brute force mental rotation/visualization power, then I bet you can probably score high on this brain game?

will unmask solution(s) submitted in about 2 days

8 Comments to “Grab a friend!”

  1. falwan | Profile (beta)

    one gets one hand and head thru string of the other and roles it thru back all the way down.


  2. Lath | Profile (beta)

    Cut the string?


  3. jbains02 | Profile (beta)

    You’d have to go thru it..


  4. michaelc | Profile (beta)

    Take a pair of siccors, and snip one of the ropes…

    no untying of the string there. :)


  5. suineg | Profile (beta)

    This puzzle is ultra cool; jajaja; I dont know is the string is long enough for this approach, but here I go:
    AreaA: area betweeen the body of person A and his string;
    AreaB: area between the body of person B and his string
    person A and B puts their string to their knee level (maybe higher if you are a ballet dancer or a yoga instructor) then person B gets his right foot in the AreaA, then is left foot, now gets both hands inside AreaA; now personA moves is string up and they are released, cool. not so easy to explain.


  6. ennui | Profile (beta)

    This problem ist equivalent to disentagling two intertwined rings, which, as it can easily be seen, is impossible:
    http://img216.imageshack.us/im.....ingxw5.png


  7. bilbao | Profile (beta)

    They are not closed rings since they have a weak point at the wrists.
    let’s imagine: both A and B tighten their strings (perpendicular) by separating their hands; A’s string is inside the ‘ring’ of B; A moves his string towards B’s wrist; take some of A’s string through the lace in B’s wrist; go round B’s hand with A’s string; bring back A’s string through B’s lace…and you are out
    Not easy to explain


  8. RK | Profile (beta)

    Somehow thought I’d see a few scissors come out on this one :)

    Here’s the official answer I have: B makes a loop of his string, passes under either of the loops of A’s hand and slips it over the hands, and both will be free.


Leave a Reply

All comments are moderated and may not appear live immediately.

To comment log in or register for a free Smartkit account.